Team Analysis – Assessing Pulis’ West Brom

Ouch, sorry. Lame IT question at the top of the page.

What browser?

Yeah I do at time, but it only happens after I erase my cookies/history. Mainly has to with my location though, as it translates everything into Spanish as well.

Once I change the Language back to english, everything goes back to normal

I've had this before and had to clear cookies and history, close down and re-boot and re-open browsers. Worked a few times, then I started using Google Chrome instead of IE and have not had a problem since.

Don't lie to us Zan ... you'll be having those dreams anyway?

So sorry to bring this onto the new unsoiled page 😳

😆

Looks really good, although I'd be tempted to play Clyne ahead of PVA and have Puncheon first sub if ADM doesnt play.

Yeah that sounds good. You think Cisse will get a start at City, Newcastle fan friend?

Looks fine.
Longer term would be looking ADM to erik for the double and Giroud to Costa.

Maybe even add to that Downing/Puncheon right down and Silva to Sanchez? (all longer term)

Team is fine, just bored and thinking out loud

Good move, have you considered Naughton as well? Maybe Bellerin instead?

boyd , colback , jwp

Ibe short term

mahrez, bolasie, boyd, jwp, colback, gil, mutch

No need to sell wisdom. I'd just replace marney and bank the other one

Can't really argue against those moves, might feel a little sideways but is setting you up nicely for the blanks.

Could you just do Wisdom > Naughton or Haidara (better GW27 fixture) and then save the 2FTs for the DGW?

Bad use of 2 FT's, IMO.
Take Wisdom out next week if you can, as you can get away with it.
I'd only do one of those moves, and I wouldn't go for Flecther myself

Looks good.
Just long term would be looking at Wally to Erik for the double

I'd get any one of Naughton or Lescott, IMO.

Great in theory. Hope it works out!

Just assuming chelsea doesn't have dgw28 or do you know something?

Looks really good, obviously needs some flexibility when Aguero does his hamstring, Sanchez catches a cold and Costa gets his 10th yellow card!

Sorry all boss called. Thanks all for replies

Eriksen or noone from the mids

Eriksen really, maybe Dembele if he's penned in the hole for a few more games. One to monitor

Hi, hat!

Howdy

Morning Titfer, how's it going?

Tip of the hat to you sir.

A tip o' the cap to ya!

I've had a dull few weeks, it feels like fantasy football has been gone for ages! Plus I need a job 🙁

No,Yes,no

All makes sense Enlightener. How about?

Chester- Bellerin
Boyd - Siggy
Defoe - Naismith

Just an option. Which I used all my available brain power on fyi. 😉

Yeah sounds good. Would put Fonte first sub.

He filled the sheet with numbers?

"your exact weight"?

This is similar to the riddle from Planescape Torment that the Skeleton gives you!

He wrote every possible weight on the piece of paper?

He wrote. Your exact weight. on it.

Alright next riddle

Most likely ... Zabaletta, Kolarov, Clichy, Sagna ... it's hard to pick a winner.

They're a little leaky at the back anyways so not as much of an issue.

Probably best to avoid. They don't seem to try and keep clean sheets when they are 3 goals up anyway

Sounds like BDSM

It's a photograph

ye olde ice block

I know this one but I won't ruin it.

You guys are good, will have dig up a long and compliacted one then. Prepare yourselves

it's all over the world , very popular among asian african countries too

ask about which village left/right will lead to

hmm I feel like I've heard this one before but can't figure it out 🙁

Point down one road and say 'are you from this village?'

ask ''which village are you from , left or right one''

Would a man from your village say this way is the way to a village of truth?

If they answer "Yes" you are pointing towards the village of truth. If "No" you are pointing to the liars.

Logic tree behind it:

If the man is from truth - he will tell you the truth.

If he is from liars - he will tell you the opposite of the question, but the question itself invokes the liars by referring to his village. Hence, you are invoking a double negative.

Ask the stranger to show you the way back to his village. If he's lying he'll show you to the village of truth and if he's telling the truth he'll also show you the way to the village of truth.

The second question was ridiculously stupid considering it's pretty much the same as the first.

WHERE ZASA GO 😡

Ask the man if he is lying to him.

🙄

Feck me I got a headache just reading that.

The doctor is his mother? 🙂

a)

C

E)

Shite, this was nice one

Charlize Theron

kate upton

Charlize for sure, Anniston's hitting the wall

This question is sooooo 1997.

can 1 rower do all the jobs or each can only rows once ?

I don't know the answer to this fwiw

😡 I just woke up 🙄

Needs to be better worded to understand how does two rowers in a boat impact the timing.

On face value, it can be done in 2 mins. R1 takes R4 and R2 takes R3.

120 feet wide.

R1 takes each of the others across separately
19mins
1140ft

I am not clear on this. When you say rowers need 1,2,6 and 9 minutes alone, how does that impact the paired speed?

Sorry gents, here it is in it's entirety

Four rower-mathematicians wish to cross the river by means of a boat that can only hold two men. The rower R₁needs 1 minute to cross the river alone, R₂, R₃, R₄need
2, 6, and 9 minutes respectively. Being mathematicians, the rowers have planned an optimal strategy for crossing the river. They start to row toward the opposite river bank in a straight line. At the very moment they begin to row, a swan starts to swim over the river in a straight line with the speed of 60 feet per second. The swan reaches the opposite river bank at the exact moment when the rowers complete their transfer. How wide is the river?

- Any of the combo will do. R1 takes 1min while R4 takes 9 mins, so on average they will take 5mins together while R2 and R3 will take 4mins which means 9mins for all 4 rover to reach other side. Trying all combinations, they'll take 9mins(assuming my method is correct?).
- 9mins
- 9 x 60 = 540feets

R1, R4 cross
R1 returns
R2, R3 cross
R2 returns
R1, R2 cross

Help?

So where are you copying and pasting these riddles from?

One rower is not optimal guys, a joined pair of rowers will cross the river faster than each of them individually

3m47.4s and 13,645.7ft (or 227.4ft depending on which speed)

Alright here is the documented solution guys,

Here goes:

First, notice that a joined pair of rowers will cross the river faster than each of them individually. To find the speed of any pair of rowers, let us assume that an energy E is needed for one transfer. If F_k stands for the power of the rower R_k necessary for one crossing which lasts t_k minutes (k= 1,2,3,4), then

E=F₁t₁=F₂t₂= F₃t₃=F₄t₄(ref.A)

where t₁=1, t₂= 2, t₃=6, t₄=9
(expressed in minutes).

From ref.A (above)it follows that

F_k = E/t_k. The time t_ij for crossing the river by any two rowers R_i and R_j is equal to

t_ij = E/F_i+F_j = E/E/t_i+E/t_j = t_it_j/t_i+t_j.

Let -->R and R₁R4 t₁₄=t₁t₄/(t₁+t ₄)= 9/10 min.

2. R₂R₃ t ₂₃=(t₂t₃/(t₂+t₃)= 3/2 min.

4. R₁R₂ t₁₂= 2/3 min.

From the above scheme we find that the total time of all transfers of the rowers is:

t = t₁₄+ t₁+ t₂₃+ t₂+ t₁₂=
9/10 + 1 + 3/2 + 2 + 2/3 =
91/15 min.

The width of the river is equal to the distance traveled by the swan:

(60 ft./min.) x (91/15 min.)=
364 ft.

Answer: 364ft.